Why is the rate of acetone iodination independent of the concentration of molecular iodine (zero-order in [I₂])?
In chemical kinetics, an overall reaction often comprises a sequence of consecutive elementary steps. The macroscopic reaction rate is strictly dictated by the slowest elementary step in the pathway—termed the rate-determining step (RDS)—along with any preceding equilibria. In the acid-catalyzed iodination of acetone, the reaction proceeds via two distinct stages: (1) the slow, acid-catalyzed enolization of acetone to form the neutral enol isomer (CH₃C(OH)=CH₂), and (2) the rapid electrophilic attack of molecular iodine upon the enol double bond to produce monoiodoacetone and iodide.
Applying the steady-state approximation (SSA) to the reactive enol intermediate demonstrates this zero-order dependence mathematically. The net rate of enol formation is d[enol]/dt = k₁·[CH₃C(OH⁺)CH₃]·[H₂O] − k₋₁·[enol]·[H₃O⁺] − k₂·[enol]·[I₂] ≈ 0. Because electrophilic halogenation is diffusion-controlled (k₂ ≈ 10⁹ L·mol⁻¹·s⁻¹), the trapping rate of the enol by iodine overwhelmingly exceeds the rate of reverse ketonization (k₂·[I₂] ≫ k₋₁·[H₃O⁺]). Consequently, virtually every enol molecule formed is immediately halogenated, yielding a tiny steady-state intermediate concentration ([enol] ≈ 10⁻¹⁰ M). The rate of iodine consumption simplifies to: −d[I₂]/dt = k₂·[enol]·[I₂] = k₁·[CH₃C(OH⁺)CH₃]·[H₂O] = k·[acetone]·[H⁺]. Because [I₂] cancels out entirely, the reaction rate is completely invariant with respect to iodine concentration ([I₂]⁰). Varying [I₂] alters only the total time elapsed until the solution decolorizes, without changing the instantaneous rate of decolorization.